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(2/x+3)-(3/4-x)=2x-2/x^2-x-12
We move all terms to the left:
(2/x+3)-(3/4-x)-(2x-2/x^2-x-12)=0
Domain of the equation: x+3)!=0
x∈R
Domain of the equation: 4-x)!=0
We move all terms containing x to the left, all other terms to the right
-x)!=-4
x!=-4/1
x!=-4
x∈R
Domain of the equation: x^2-x-12)!=0We add all the numbers together, and all the variables
x∈R
(2/x+3)-(-1x+3/4)-(2x-2/x^2-x-12)=0
We get rid of parentheses
2/x+1x-2x+2/x^2+x+3+12-3/4=0
We calculate fractions
We do not support expression: x^3
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